40x^2+350=50x^2+250

Solution for 40x^2+350=50x^2+250 equation:

40x^2+350=50x^2+250

We move all terms to the left:

40x^2+350-(50x^2+250)=0

We get rid of parentheses

40x^2-50x^2-250+350=0

We add all the numbers together, and all the variables

-10x^2+100=0

a = -10; b = 0; c = +100;
Δ = b2-4ac
Δ = 02-4·(-10)·100
Δ = 4000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4000}=\sqrt{400*10}=\sqrt{400}*\sqrt{10}=20\sqrt{10}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20\sqrt{10}}{2*-10}=\frac{0-20\sqrt{10}}{-20}
=-\frac{20\sqrt{10}}{-20}
=-\frac{\sqrt{10}}{-1}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20\sqrt{10}}{2*-10}=\frac{0+20\sqrt{10}}{-20}
=\frac{20\sqrt{10}}{-20}
=\frac{\sqrt{10}}{-1}
$